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log(x-y)-log5-1/2logx-1/2logy=0 then fin...

`log(x-y)-log5-1/2logx-1/2logy=0` then find the value of `y/x+x/y=?`

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`log(x-y) - log5 -1/2logx - 1/2logy = 0`
`=>log(x-y) - log5 -1/2(logx + logy) = 0`
`=>log(x-y) - log5 -1/2(logxy) = 0`
`=>2log(x-y) - 2log5 -(logxy) = 0`
`=>log(x-y)^2 - log5^2 -(logxy) = 0`
`=>log(x-y)^2 -(logxy) = log5^2`
`=>log((x-y)^2/(xy)) = log25`
`=>(x-y)^2/(xy) = 25`
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