[" 1."x+2y+1=0],[" 2x-3y-12"=0]

Solve by cross multiplication x+2y+1=0 ,2x-3y-12=0

Solve the following system of equations by method of cross-multiplication: x+2y+1=0,\ \ \ \ 2x-3y-12=0

Solve the following system of equations by method of cross-multiplication: x+2y+1=0,quad 2x-3y-12=0

All points lying inside the triangle formed by the points (1.3).(5,0) and (-1,2) satisfy (A)3x+2y>=0 (B) 2x+y-13>=0 (C) 2x-3y-12 =0

If (2, -2),(-1,2), (3,5) are the vertices of a triangle then the equation of the side not passing through (2,-2) is (A) x + 2y +1 = 0 (B) 2x - y- 4= 0 (C) X-3y -3= 0 (D) 3x – 4y + 11 = 0

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0

Show that the lines 2x+3y + 11 =0 and 2x-2y-1=0 are conjugate with respect to the circle x^(2) + y^(2) + 4x+ 6y +12 = 0

Show thet the lines 2x+3y + 11 =0 and 2x-2y-1=0 are conjugate with respect to the circle x^(2) + y^(2) + 4x+ 6y +12 = 0

The orthocentre of a triangle formed by the lines x-2y = 1, x=0 and 2x +y -2 =0 is a) (0,1) b) (1,0) c) (-1,-2) d) (1,2)