[" 12.यक्ष "(1)/(x):(1)/(y):(1)/(z)=2:3:5" हो,तो "x:y:z=?],[[" (a) "2:3:5," (b) "15:10:6," (c) "5:3:2," (d) "6:10:15]]

If (1)/(x) : (1)/(y):(1)/(z) = 2 : 3 : 5 , then x : y : z = ?

If (1)/(x) : (1)/(y) : (1)/(z) = 2 : 3 : 5 then determine x : y :z

(2-3x)/(x)+(2-3y)/(y)+(2-3z)/(z)=0 then (1)/(x)+(1)/(y)+(1)/(z)=

1/x+1/y+1/z=1,2/x+5/y+3/z=0,1/x+2/y+4/z=3

Using Cramer's rule solve (1)/(x)+(1)/(y)+(1)/(z)=1,(2)/(x)+(5)/(y)+(3)/(z)=0,(1)/(x)+(2)/(y)+(4)/(z)=3

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

1//x-1/y+1/z=4, 2/x+1/y-3/z=0, 1/x+1/y+1/z=2(x,y,z ne 0)