" If "alpha=(pi)/(3)," prove that "cos alpha cos2 alpha cos3 alpha cos4 alpha cos5 alpha cos6 alpha=-(1)/(16)

If alpha = (pi)/(13), Prove that cos alpha cos 2alpha cos 3alpha cos 4alpha cos 5alpha cos 6alpha = (1)/(64) .

If alpha = pi/3, prove that cos alpha*cos 2alpha*cos 3alpha*cos 4alpha*cos 5alpha*cos 6alpha = -1/16.

If alpha = pi/3 , prove that cos alpha*cos 2alpha*cos 3alpha*cos 4alpha*cos 5alpha*cos 6alpha = -1/16 .

If alpha = pi/3 , prove that cos alpha*cos 2alpha*cos 3alpha*cos 4alpha*cos 5alpha*cos 6alpha = -1/16 .

If alpha=(pi)/(17), show that (cos alpha cos13 alpha)/(cos3 alpha+cos5 alpha)=-(1)/(2)

Prove that sin^2alpha-sin^4alpha= cos^2alpha-cos^4alpha

cos alpha cos 2 alpha cos 4 alpha cos 8 alpha = (1)/(16), if alpha = 24 ^(@)

cos2 alpha-cos3alpha-cos4alpha+cos5alpha simplifies to :

cos2 alpha-cos3alpha-cos4alpha+cos5alpha simplifies to :

sin alpha-sin2 alpha+sin3 alpha=4cos(3 alpha)/(2)cos alpha sin(alpha)/(2)