`O^(2-)` and `Si^(4+)`are isoelectronic ions. If the ionic radius of `O^(2-)` is 1.4 `oversetoA`, the ionic radius of `Si^(4+)` will be

Options

A. `1.4 oversetoA`
B. `0.41 oversetoA`
C. `2.8 oversetoA`
D. `1.5 oversetoA`

Answer

B

Explanation

`Si^(4+)` has less ionic radius compared to 02- because of more positive charge and high nuclear charge in `Si^(4+)`.
`O^(2-) = 10e^(-) = 8p` nuclear charge.
`Si^(4+) - 10e^(-) = 14p` nuclear charge.
therefore The ionic radius of Si must be less than 1.4 A ie., 0.41A.