The bond length of HCl molecule is `1.275 A^(@)` and its dipole moment is 1.03 D. The ionic character of the molecule (in per cent) (charge of the electron `-4.8xx10^(-10)-esu`) is

Options

A. 100
B. 67.3
C. 33.66
D. 16.83

Answer

(d)

Explanation

Dipole moment of HCl molecule = 1.03 D
  = `1.03xx10^(-18)esu-cm`
Bond length of HCl molecule (d) = `1.275 A^(@)`
= `1.275xx10^(-8) cm`
Charge of electron (e) = `4.8 xx 10^(-10) esu`
Percentage of ionic character
= `("Observed dipole moment")/("Theoretical dipole moment")xx100`
=`(1.03xx10^(-18))/(4.8xx10^(-10)xx1.275xx10^(-8))xx100`
(because Dipole moment = charge of `e^(-)`Bond length)
=`(1.03xx10^(-18))/(6.12xx10^(-18))xx100`
=`(1.03)/(6.12)xx100`
=16.83