The oxidation state of Xe in `XeO_(3)` and the bond angle in it respectively, are

Options

A. `+6,109^(@)`
B. `+8,103^(@)`
C. `+6,103^(@)`
D. `+8,120^(@)`

Answer

( c)

Explanation

Oxidation state of oxygen = -2
Let oxidation state of Xe in `XeO_(3) = x`
`therefore x+(-2xx3) = 0`
X-6=0
X = +6
`XeO_(3)` has `sp^(3)` hybridisation and pyramidal structure with bond angle of `103^(@)`.