If the bond length and dipole moment of a diatomic molecule are 1.25 `A^(@)` and 1.0 D respectively, what is the percent ionic character of the bond ?

Options

A. 10.66
B. 12.33
C. 16.66
D. 19.33

Answer

( c)

Explanation

Oxidation state of oxygen = -2
Let oxidation state of Xe in `XeO_(3) = x`
` therefore x+(-2x3) = 0`
X-6=0
X = +6
`XeO_(3)` has `sp^(3)` hybridisation and pyramidal structure with bond angle of `103^(@)`. 28. Answer ) Bond length of diatomic molecule, `d = 1.25 A^(@)`
= `1.25 xx 10^(-8) cm`
Experimental value of dipole moment = 1.0D
=`1.0xx10^(-18)esu cm `
Charge of electron = `4.8 xx 10(-10)esu`
Percentage of ionic character,
`("Experimental value of dipole moment")/("Theoretical value of dipole moment")xx100`
  `(1xx10^(-18))/(1.25xx10^(-8)xx4.8xx10^(-10))xx100` = `16.66`