An organic compound haavig C, H and O has 13.13% H, 52.14% C and 34.73% O. its molar mass is 46.068 g. What are its empirical and molecular formulae?

Options

A. `C_(2)H_(6)0, C_(4)H_(12)O_(2)`
B. `CH_(3)0, C_(2)H_(6)O_(5)`
C. `C_(2)H_(6)0, C_(2)H_(6)O`
D. `C_(2)H_(6)0_(2), C_(3)H_(9)O_(4)`

Answer

(c )

Explanation

Empirical formula = `C_(2)H_(6)O`
Empirical weight =2 x 12 + 6 ×1 +1 x 16= 46
Molecular weight = 46.068
Since molecular weight= empirical weight
`:.`Empirical formula molecular formula `=C_(2)H_(6)O`.