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The number of moles of electrons require...

The number of moles of electrons required to deposite 36 g of Al from an aqueous solution of `Al(NO_(3))_(3)`, is (At. wt. of Al = 27)

A

4

B

2

C

3

D

1

Text Solution

Verified by Experts

The correct Answer is:
(a)
`Al^(3+) + 3e^(-) rarr Al`
3 moles of electrons are required for depositing 27g of Al.
`:.`x moles of electrons are required for depositing 36g of Al
`x = (3 xx 36)/27`
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