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Calculate the heat of combustion (in kJ ) of the methane from the following data.(I) `C_(graph ite)+2H_(2)(g)toCH_(4)(g)," " DeltaH=-74.8kJ`
II `C_(grap hite)+O_2(g)toCO_2(g)," "DeltaH=-3935kJ`
III `H_(2)(g)+(1)/(2)O_(2)(l)" " Delta=-286.2kJ`

A

`-891.1`

B

`816.3`

C

`-965.9`

D

`-1040.7`

Text Solution

Verified by Experts

The correct Answer is:
A
Step 1 : Reverse equation(I)`CH_(4)(g)toC(graph ite)+2H_(2)(g),DeltaH=+74.8kJ`
Steps2:Multtiply euquations (III) and (II)
`2H_(2)(g)+O_(2)(g)to2h_(2)o,DeltaH=-572.4`
Adding equations (I),(II),(III)
`CH_(4)toC+2H,DeltaH=+74.8kJ`
`C+O_(2)toCO_(2),DeltaH=-393.5`
underlne (`2H_(2)+O_(2)to2H_(2)O,DeltaH=-572.4`)
`CH_(4)+2O_(2)toCO_(2)+2H_(2)O,DeltaH=-891.1kJ`
`therefore` Heat of combustion is -891.1kJ
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