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The pH of 0.05 M acetic acid is (K(a) = ...

The pH of 0.05 M acetic acid is `(K_(a) = 2 xx 10^(-5))`

A

2

B

11

C

`10^(-3)`

D

3

Text Solution

Verified by Experts

The correct Answer is:
D
In weak acids,concentration of `H^(+)` ion is given by
`[H^(+)] = sqrt(K_(a) xx [HA])`
`[H^(+)] = sqrt(2 xx 10^(-5) xx 0.05) = sqrt(10^(-6)) = 10^(-3)`
`:. pH = -"log"(H^(+)) = -"log"(10^(-3)) = 3`
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