If the equilibrium constant for the reaction,`H_(2)(g) +I_(2)(g) hArr 2HI(g)` is K
What is the equilibrium constant of `HI(g) rarr 1/2 H_(2)(g) + 1/2I_(2)(g)`?

Options

A. `1/K`
B. `sqrt(K)`
C. K
D. `1/sqrt(K)`

Answer

D

Explanation

(i) `H_(2) + I_(2) hArr 2HI`
`K = [HI]^(2)/([H_(2)][I_(2)])`…………(1)
(ii)` HI = 1/2H_(2) + 1/2 I_(2)`
`K_(1) = ([H_(2)]^(1/2)[I_(2)]^(1/2))/[HI]`……………..(2)
From equation (1) and (2), we get
`K_(1) = 1/sqrt(K)`