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50 ml of H(2)O is added to 1 xx 10^(-3)M...

50 ml of `H_(2)O` is added to `1 xx 10^(-3)`M barium hydroxide solution. What is the pH of the resulting solution?

A

3

B

3.3

C

11

D

11.7

Text Solution

Verified by Experts

The correct Answer is:
C

Hydrolysis of barium hydroxide in water is as follows.
`Ba(OH)_(2) hArr Ba^(2+) + 2OH^(-)`
`[OH^(-)] = 2 xx [Ba(OH)_(2)]/2`
`pOH = -"log"[OH^(-)] = -"log"[1 xx 10^(-3)] = -(-3)"log"_(10) = 3`
pH = 14 - pOH = 14 - 3 = 11
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