Consider the following reaction equilibrium
`N_(2)(g)+ 3H_(2)(g) hArr 2NH_(3)`
Initially, 1 mole of `N_(2)` and 3 moles of `H_(2)` are taken in a 2 2L flask. At equilibrium state, if the number of moles of `N_(2)` is 0.6, what is the total number of moles of all gases present in the flask?

Options

A. 0.8
B. 1.6
C. 3.2
D. 6.4

Answer

C

Explanation

Number of moles of `N_(2) x = 1 - 0.6 = 0.4`
Number of moles of `H_(2) = 3 - 3x = 3 -3 xx 0.4 = 1.8`
Number of moles of `NH_(3) = 2x = 2 xx 0.4 = 0.8`
`:.` Total number of moles of all gases =` 0.6 + 1.8 + 0.8 = 3.2`