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At 90^(circ)C, the concentration of H(3)...

At `90^(circ)C`, the concentration of `H_(3)O^(+)` inpure water is `10^(-6) mol L^(-1)`. What is the value of `K_(w)` at this temperature?

A

`10^(-6)`

B

`10^(-8)`

C

`10^(-14)`

D

`10^(-12)`

Text Solution

Verified by Experts

The correct Answer is:
D

Given that,
`[H_(3)O^(+)] = 10^(-6) mol L^(-1)`
`K_(W) = [H_(3)O^(+)][OH^(-)] = 10^(-6) xx 10^(-6) = 10^(-12) mol L^(-1)`
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