Home
Class 12
CHEMISTRY
In aqueous solutions, H(2)O(2) oxidises ...

In aqueous solutions, `H_(2)O_(2)` oxidises `H_(2)S` to

A

Sulphur

B

Sulphuric acid

C

Sulphurous acid

D

Marshall's acid

Text Solution

Verified by Experts

The correct Answer is:
(a)
In aqueous solutions, `H_(2)O_(2)` oxidises `H_(2)S` to form sulpur.
`H_(2)O_(2) + H_(2)S rarr 2H_(2)O+S`
Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER

    SIA PUBLICATION|Exercise CHEMISTRY|32 Videos

  • SAMPLE PAPER 2017

    SIA PUBLICATION|Exercise CHEMISTRY|37 Videos

Similar Questions

Explore conceptually related problems

In aqueous solutions H_(2) SO _(4) ionises as: H _(2) SO_(4) + H _(2) O hArr H _(2) SO _(24 ) ^(-) + H _(3) O ^(+) , K a _(1) H_(2) SO _(4) ^(-) + H_(2) O hArr SO _(4) ^(2-) + H_(3) O ^(+) , Ka _(2). The relation between Ka _(1) and Ka _(2) is

An aqueous solution of H_(2)O_(2) is purified by

An aqueous solution of H_(2)O_(2) is labeled as 33.6 vol. The amount of H_(2)O_(2) present is 50ml of such an aqueous solution is

H_(2)O_(2) oxidised the following

(A) SO _(2) acts as good reducing agent in aqueous solutions (R ) SO _(2) + 2 H _(O to H _(2) SO _(4) + 2 (H)

Chlorine oxidises H_2 S to

Aqueous solution of H_(2)S contains H_(2)S, HS^(-),S^(2-),H_(3)O^(+),OH^(-) and H_(2)O in varying concentrations. Which of these species can act only as a base? Which can act only as an acid? Which can act both as an acid and as a base?

An aqueous solution of [Ti(H_2O)_6]^(+3) appears

If x' litres of O_(2) is released at STP from one litre of H_(2)O_(2) solution due to decomposition of H_(2)O_(2) then we lable such solution as 'x volume H_(2)O_(2) 2H_(2)O_(2) to 2H_(2)O+O_(2) 30% (w/v) H_(2)O_(2) is called perhydrol. How much volume of 11.2 volumes H_(2)O_(2) is required to completely oxidise one mole of lead sulphite into lead sulphite?