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The mole fraction of solute in 20% aqueo...

The mole fraction of solute in 20% aqueous `H_(2)O_(2)` solution is

A

0.588

B

0.444

C

0.1168

D

4.44

Text Solution

Verified by Experts

The correct Answer is:
(c )
In 20% aqueous `H_(2)O_(2)`,
Number of moles of `H_(2)O_(2)` = 0.588
In 80%, number of moles of `H_(2)O_(2)` = 4.444
`:.`Mole fraction of solute in 20% aq. `H_(2)O_(2)`
= `("Number of moles of H_(2)O_(2)")/ ("Total number of moles")`
`= 0.588/(0.588 + 4.444) = 0.1168`
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