1.5 of CdCI3 was found to contain of 0.9...

1.5 of `CdCI_3` was found to contain of 0.9 g of Cd. Calculate the atomic of Cd.

118

112

106.5

53.25

Text Solution

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The correct Answer is:

weight of `CdCl_2 = 1.5g`
Weight of cd = 0.9g
% of Cd in CdCl, `=( 0.9)/1.5 xx 100 = 60`%

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