Ferrous ion changes to X ions , on reacting with acidified hydrogen peroxide . The number of d- electrons present in X and its magnetic moment (in BM) are , respectively

Options

A. 6and 6.93
B. 5and 5.92
C. 5 and 4.9
D. 4 and 5.92

Answer

(b)

Explanation

`(2K_4[Fe(CN)_6]+H_2SO_4) + (H_2O_2 to 2k_3) [ Fe(CN)_6]` + `(K_2SO_4 + 2H_2O)`
In the above reaction , ferrous ion `(Fe^(2+))` on reaction with `H_2O` changes to ferric ion `(Fe^(3+))`.
Electronic configuration of `Fe^3+= [Ar]3d^5` (Number of unpaired 'd' electrons , n= 5) Therefore Magnetic moment = `sqrt n(n+r) = sqrt 5(5+2) = sqrt35)`
= 5. 92 BM.