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The oxidation state of Mo in (MO2Cl8)^(4...

The oxidation state of Mo in `(MO_2Cl_8)^(4-)` ion is

A

(-)4

B

(-)2

C

(+)6

D

(+)2

Text Solution

Verified by Experts

The correct Answer is:
(d)
Oxidation state of Moin `(MO_2Cl_8)^4-` ion is calculated as:
`2x+8(-1) = -4
2x-8 - =-4
2x=4
therefore x=+2`
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