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In the reaction , (C2O4^2 +MnO4^- + H^+ ...

In the reaction , `(C_2O_4^2 +MnO_4^- + H^+ ) to (H_2O + Mn^2+ ) + Co_2`, the reductant is

A

`MnO_4^-`

B

`H^+`

C

`Mn^2+`

D

`C_2O_4^2-`

Text Solution

Verified by Experts

The correct Answer is:
(d)
Reductant or reducing agents are the compound which undergo oxidation and reduce the other compunds.
In the given reaction , `C_2O_4^(2-)` reduces `MnO_4^(2-) to Mn^2`= by undergoing oxidation .
therefore `C_2O_4^(2-)` is the reductant .
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