The concentration of an organic compound in chloroform is 6,15 g per 100 mL of solution. A portion of this solution in a 5 cm polarimeter tube causes an observed rotation of -`1.2^(@)`. What is the specific rotation of the compound?

Options

A. `+12^(@)`
B. ` -3.9^(@)`
C. `-39^(@)`
D. `+61.5^(@)`

Answer

C

Explanation

C=6.15g
`[alpha]_("observed")`=-`1.2^(@)`
=l=5cm
therfore specific rotation of compound,
`[alpha]=([alpha]_(observed))/(lxxC)=(-1.2)/(5xx6.15/1000)=-39^(@)`