A gas 'X' is dissolved in water at '2' bar pressure. Its mole fraction is 0.02 in solution. The mole fraction of water when the pressure of gas is doubled at the same temperature is

Options

A. 0.04
B. 0.98
C. 0.96
D. 0.02

Answer

( c)

Explanation

Vapour pressure = Vapour pressure of pure solvent `(P^(0))xx"Mole fraction "(X)`
of solution (p)
P `prop` X
i.e, `(P_(1))/(P_(2))=(X_(1))/(X_(2))to (2)/(4)`=`(0.02)/(X_(2)) to X_(2)=0.04`
therefore Mole fraction of solvent (water)`=1-0.04=0.96`