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The volume in mL of 0.1 M solutions of N...

 The volume in mL of 0.1 M solutions of NaOH required to completely neutralise 100 mL of 0.3 M solution of `H_(3)PO_(3)` is

A

60

B

600

C

300

D

30

Text Solution

Verified by Experts

The correct Answer is:
(b)
`H_(3)PO_(3)` is a dibasic acid
  `0.3 MH_(3)PO_(3) = 0.6 N H_(3)PO_(3)`
`N_(1)V_(1)=N_(2)V_(2)` `0.1xx V_(1) = 0.6 x 100`
`Rightarrow` `V_(1) = (0.6 xx 100)/(0.1) = 600 ml`
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