If 20 mL of 0.4 N NaOH solution completely neutralised 40 mL of a dibasic acid, the molarity of the acid solution is

Options

A. `0.1M`
B. `0.2M`
C. `0.1=3M`
D. `0.4M`

Answer

(a)

Explanation

Normality of NaOH solution `(N_(1)) = 0.4`
Volume of NaOH solution `(V_(1)) = 20 mL`
Volume of dibasic acid solution `(V_(2)) = 40 mL`
`N_(1)V_(1)= N_(2)V_(2)`
`0.4 xx 20 = N_(2) xx 40`
`N_(2) = (0.4xx/20)/(40) = 0.2`
`therefore` Molarity of dibasic acid `(M) =( 0.2)/(2)=0.1M`