What is the slope of the straight line for the graph drawn between Ink and y, where k is the rate constant of a reaction at temperature T?

Options

A. `-E_(a)/(2.303R)`
B. `(-E_(a))/R`
C. `E_(a)/R`
D. `R/E_(a)`

Answer

B

Explanation

Arrhenius equation `k = Ae^(-Ea//RT)`
Take "log" on both sides
`lnk = lnA + ln (e^(-Ea//RT))`
`implies lnk = ln A - Ea//RT`
`implies lnk = - Ea//RT +ln A …….(1)`
y=mx+c
By comparing equations (1) and (2), we get,
` therefore` The slope of the straight line, `m=-E_(a)/R`