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What is the reduction electrode potentia...

What is the reduction electrode potential (in volts) of copper electrode, when `[Cu^(2+)]` = 0.01 M is in a solution at `25^@` C?
(`E^@` of `Cu^(2+)//Cu` electrode is + 0.34 V.)

A

0.3991

B

0.2809

C

0.3105

D

0.3695

Text Solution

Verified by Experts

The correct Answer is:
B
` E_((Cu^(2+))//(Cu))^@ =0.34V , [Cu^(2+)] = 0.01 M`
`E_(cell)=E_(cell)^@ + 0.0591/n 10g [M^(+)]`
`= 0.34 + 0.0591/n "log"_(10) [0.01][ because n=2]`
`= 0.34 + 0.0591/n "log"_(10) 10^(-2)=0.34-0.059/2 xx2`
` therefore E_(cell)=0.2809 V`
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