During the electrolytic reduction of alumina, the reaction at cathode is

Options

A. `2H_(2)O to O_(2) + 4H^(+) + 4e^(-)`
B. `3F^(-) to 3F+3e^(-)`
C. `Al^(3+) + 3e^(-) to Al`
D. `2H^(+) + 2e^(-) to H_(2)`

Answer

C

Explanation

`Al^(3+) + 3e^(-) to Al`