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The cell reaction of a cell is Mg(s) + C...

The cell reaction of a cell is
`Mg(s) + Cu^(2+)(aq) to Cu(s) + Mg^(2+)(aq)`
If the standard reduction potentials of magensium and copper are -0.33 and +2.38 V respectively, the emf of the cell is

A

+ 2.03V

B

-2.03V

C

+ 2.71V

D

-2.71V

Text Solution

Verified by Experts

The correct Answer is:
C

`E_((Mg^(2+))//(Mg))^@ = 0.33V and E_((Cu^(2+))//(Cu))^@=+ 2.38V`.
`E_(cell)^@= E_(cathode)^@-E_(anode)^@= E_((Cu^(2+))//(Cu))^@ - E_((Mg^(2+))//(Mg))^@`
`E_(cell)^@= 2.38 - (- 0.33) = + 2.71 V`.
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