The reaction taking place at the anode, when an aqueous solution of `CuSO_(4)` is electrolysed using inert Pt electrode, is

Options

A. `2SO_(4)^(2-) to S_(2)O_(4)^(2-) + 2e^(-)`
B. `Cu^(2+) + 2e^(-) to Cu`
C. `2H_(2)O to O_(2) + 4H^(+) +4e^(-)`
D. `2H^(+) + 2e^(-) to H_(2)`

Answer

C

Explanation

In the electrolysis of `CuSO_(4)` solution, the reaction at anode is, `2H_(2)O to O_(2) + 4H^(+) + 4e^(-)`