How many grams of copper would be deposited, if 3.00 A of current is passed through a solution of `CuSO_(4)` for 4h? (At. wt. of Cu = 63.54)

Options

A. 7.11
B. 14.22
C. 2844
D. 56.88

Answer

B

Explanation

`I = 3A, t = 4hrs = 4 xx 60 xx 60sec`
Weight of copper that can be deposited by `96500C=63.54/2=31.27g.`
`Q = It = 3 xx 4 xx 60 xc 60C = 43200C`.
Weigh of copper that can be deposited by 43200 C
`(31.77 xx 43200)/96,500 = 14.22g`.