The rate constant of a first order reaction at `27^@C` is `10^(-3)mi n^(-1)`. The temperature coefficient of this reaction is 2. What is the rate constant (in mi`n^(-1)`) at `17^@C` for this reaction?

Options

A. `10^(-3)`
B. `5xx10^(-4)`
C. `2xx10^(-3)`
D. `2xx10^(-3)`

Answer

B

Explanation

Temperature coefficient `= (k+10)/k`
`implies (K_(1^@ C) +10^@C)/K_(17^@C)=2`
`implies K_(17^@C)= 10^(-3)/2`
`= 5 xx 10^(-4) mi n^(-1)`