Observe the following reaction:
`2A + B to C`
The rate of formation of C is `2.2xx10^(3)` mol `L^(-1) min^(-1)`.What is the value `- (d(A))/(dt) ("in "mol L^(-1) mi n^(-1))`

Options

A. `2.2 xx I0^(-3)`
B. `1.1 xx 10^(-3)`
C. `4.4 x 10^(-3)`
D. `5.5 xx 10^(-3)`

Answer

C

Explanation

`2A + B to C and (d[C])/(dt)= 2.2 xx 10^(-3) mol L^(-1) mi n^(-1)`
Rate of Reaction `= -1/2 (d[A])/(dt)= (d[B])/(dt)= (d[C])/(dt)`
` therefore -(d[A])/(dt)=2(d[C])/(dt)=2 xx 2.2 xx 10^(-3)=4.4xx10^(-3) mol L^(-1) mi n^(-1)`