One mole of A (g) is heated to `200^@` C in a one litre closed flask, till the following equilibrium is reached.
`A(g) leftrightarrow B(g)`
The rate of forward reaction, at equilibrium, is 0.02 ` mol L^(-1) mi n^(-1)`. What is the rate (in ` mol L^(-1)mi n^(-1)`) of the backward reaction at equilibrium?

Options

A. 0.04
B. 0.01
C. 0.02
D. 1

Answer

C

Explanation

At equilibrium, rate of forward reaction « Rate of backward reaction =` 0.02 mol^(-1)L^(-1)mi n^(-1)`