Equilibrium constant for the reaction, `H_(2)O (g) + CO(g)` is 81. If the velocity constant of the forward reaction is 162 L mol `s^(-1)`, what is the velocity constant (in ` mol s^(-1)`) for the backward reaction?

Options

A. 13122
B. 2
C. 261
D. 243

Answer

B

Explanation

`K_(c) =81` and `K_(f)=162L mol^(-1)s^(-1)`
`K_(c)=K_(f)/K_(b) implies K_(b)= K_(f)/K_(c)=162/81=2`
`therefore` Velocity constant for backward reaction, `K_(b)=2`.