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The time tor half - life of a first orde...

The time tor half - life of a first order reaction is 1 h. What is the time taken for 87.5% completion of the reaction?

A

lh

B

3h

C

2h

D

4h

Text Solution

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The correct Answer is:
C

`t_(1.2)=1h`
`k=0.693/t_(1/2)=0.693/1=0.693`
`therefore t_(87.5%)=2.303/k "log"_(10) (100/12.5)= 2.303/0.693 xx 0.9030=3h`
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