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The foci of the ellipse (x^2)/(16)+(y^2)...

The foci of the ellipse `(x^2)/(16)+(y^2)/(b^2)=1` and the hyperbla `(x^2)/(144)-(y^2)/(81)=(1)/(25)` coincide. Then, the value of `b^(2)` is

A

7

B

1

C

9

D

5

Text Solution

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The correct Answer is:
A
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