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A particle is projected from the ground ...

A particle is projected from the ground with an initial speed of u at an angle of projection `theta`. The average velocity of the particle reaches highest point of trajectory is

A

`(V)/(2)sqrt(1+2cos^(2)theta`

B

`(V)/(2)sqrt(1+2sin^(2)theta`

C

`(V)/(2)sqrt(1+3cos^(2)theta`

D

`V cos theta`

Text Solution

Verified by Experts

The correct Answer is:
C
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A particle is projected from the ground with an initial speed of V at an angle of projection theta . The average velocity of the particle between its time of projection and time it reaches highest point of trajectory is

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