40 mol of `underline(x) M KMnO_4` solution is required to react completely with 200 ml of 0.02 M oxalic acid solution in acidic medium. The value of `underline(x)` is

Options

A. 0.04
B. 0.01
C. 0.03
D. 0.02

Answer

A

Explanation

Give that
`M_1 =x M_(2) =0.02`
`V_(1) =40 ml V_(2) =200`
`n_(1) =2 n_(2) =5`
`(M_1V_1)/(n_1) (KMnO_4)=(M_2V_2)/(n_2) (underset(COOH)underset(|)(COO)H)`
`rArr (x xx 40 ml)/(2)=(0.02 xx 200 ml)/(5)`
`x=(0.02 xx 200 ml )/(5) xx (2)/(40)`
`x=0.8 xx 0.05`
`x=0.04 M`.