The slope of the graph drawn between ln k and 1/T as per Arrhenius equaiton gives the value (R= gas constant, `E_(a)=` Activation energy) .

Options

A. `( R)/(E_a)`
B. `(E_a)/( R)`
C. `(-E_a)/( R)`
D. `(- R)/(E_a)`.

Answer

C

Explanation

`K=Ae^(-Ea//RT)`. (Arhenius equation)
By applying log, we get
`log K=log A -( E)/(2.303 RT)`
`In K= In A-( E_a)/(RT)`