A bird is tossing (flying to and pro) between two cars moving towards each other on a straight road. One car has speed of `36Kmh^-1.` The bird starts moving from first car towards the other and is moving with the speed of `36Kmh^-1.` when the two cars were separated by 36 km. The total distance covered by the bird before the cars meet each other is

Options

A. 1440m
B. 24400m
C. 244m
D. 14400m

Answer

D

Explanation

Answer(4) Relative speed of cars = 54 + 36 = 90 Km/hr
Time taken by each car to meet each other, t = 36/90 = 0.4h .
Distance travelled by bird in 0.4h = 36[t] = 36(0.4) = 14.4 km `therefore D = 14400m` .