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The enthalpy of formation (DeltarH) of m...

The enthalpy of formation `(Delta_rH)` of methanol, formaldehyde and water -239, -116 and -286KJ`mol^-1` respectively. The enthalpy change for the oxidation of emthanol to formaldehyde and water in KJ is

A

-136

B

-173

C

-163

D

163

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Verified by Experts

The correct Answer is:
C

Answer(3) Enthalpy change `[DeltaH] = sum Delta_f `H[Products] - `sum Delta_f H`[Reactants]
(-116 -286) - (-239) .
`therefore DeltaH = -163`
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