The equilibrium constant (`K_c`) for the following equilibrium `2So_(2(g)) + O_(2(g)) iff 2SO_(3(g))` at 563K is 100. at equilbrium, the number of moles of `SO_3` in the 10 litre flask is twice the number of moles of `SO_2`, then the numbers of moles of oxygen is

Options

A. 0.3
B. 0.4
C. 0.1
D. 0.2

Answer

B

Explanation

Answer(2) Given, volume, V = 10 litres
At equilibrium, `SO_3 = 2[SO_2]`
Equilibrium constant, `K_c = [SO_3]^2/[SO_2]^2[O^2] = 100`
100 = `[2SO_2]^2/[SO_2]^2 xx 10/ ("Number of moles of "O_2)`
100 = `4 xx10/ ("Number of moles of" O_2)`
`[O_2]_moles = 4 xx 10/100 =0.4`