Home
Class 12
MATHS
The equation of the tangent at the point...

The equation of the tangent at the point (0, 3) on the circle which cuts the circles `x^(2)+y^(2)-2x+6y=0`,
`x^(2)+y^(2)-4x-2y+6=0` and
`x^(2)+y^(2)-12x+2y+3=0` orthogonally is

A

`y=3`

B

`x=0`

C

`3x+y -3=0`

D

`x+3y-9=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • EAMCET - 2018 (TS) SHIFT - 1

    SIA PUBLICATION|Exercise EXERCISE - Physics|35 Videos
  • EAMCET - 2018 (TS) SHIFT - 1

    SIA PUBLICATION|Exercise EXERCISE - Chemistry|8 Videos
  • DIFFERENTIATION

    SIA PUBLICATION|Exercise Problems|50 Videos
  • EAMCET - 2018 (TS) SHIFT - 2

    SIA PUBLICATION|Exercise Chemistry|18 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the circle which cuts the circles x^2+y^2+4x+2y+1=0, 2(x^2+y^2)+8x+6y-3=0 and x^2+y^2+6x-2y-3=0 orthogonally.

The locus of the centre of the circle which cuts the circles x^(2) + y^(2) + 4x - 6y + 9 = 0 " and " x^(2) + y^(2) - 4x + 6y + 4 = 0 orthogonally is

The locus of the centre of the circle which cuts the circles x^(2) + y^(2) + 4x - 6y + 9 = 0 " and " x^(2) + y^(2) - 5x + 4y + 2 = 0 orthogonally is

The radical centre of the circles x^(2) + y^(2)- 2x + 6y = 0 , x^(2) + y^(2) - 4x - 2y + 6 = 0 , x^(2) + y^(2) - 12x + 12y + 30 = 0 is

The equation of the circle which cuts the three circles x^2+y^2-4x-6y+4=0, x^2+y^2-2x-8y+4=0, x^2+y^2-6x-6y+4=0 orthogonally is

The equation of the common tangent at the point contact of the circles x^(2) + y^(2) - 10x + 2y + 10 = 0 , x^(2) + y^(2) - 4x - 6y + 12 = 0 is

A circle S cuts three circles x^(2) + y^(2) - 4x - 2y + 4 = 0 , x^(2) + y^(2) - 2x - 4y + 1 = 0 " and " x^(2) + y^(2) + 4x + 2y + 1 = 0 orthogonally . Then the radius of S is