If (alpha,beta) and (gamma,delta) where ...

If `(alpha,beta)` and `(gamma,delta)` where `alpha lt gamma`, are the turning points of `f(x)=2x^(3)-15x^(2)+36x-8`, then `alpha-gamma-beta+delta=`

A

0

B

`-2`

C

2

D

1

Verified by Experts

The correct Answer is:

B

EAMCET - 2018 (TS) SHIFT - 1
SIA PUBLICATION|Exercise EXERCISE - Physics|35 Videos
EAMCET - 2018 (TS) SHIFT - 1
SIA PUBLICATION|Exercise EXERCISE - Chemistry|8 Videos
DIFFERENTIATION
SIA PUBLICATION|Exercise Problems|50 Videos
EAMCET - 2018 (TS) SHIFT - 2
SIA PUBLICATION|Exercise Chemistry|18 Videos

Similar Questions

Explore conceptually related problems

If alpha, beta, gamma are the roiots of x^(3) - 10x^(2) +6x - 8 = 0 then alpha^(2) + beta^(2) + gamma^(2) =

If alpha , beta , gamma are the roots of x^3 +2x^2 +3x +8=0 then (3-alpha )(3 - beta) (3-gamma) =

If alpha, beta, gamma are the roots of x^(3) - 3x + 7 = 0 then alpha + beta + gamma =

If alpha, beta,gamma are roots of x^(3) - px^(2) + qx - r = 0 then sum alpha (beta + gamma) =

If alpha,beta, gamma are the roots of 4x^(3) - 6x^(2) + 7x + 3 = 0 then alpha beta + alpha beta + alpha gamma =

If alpha, beta, gamma are the roots of x^(3) + x^(2) + x + 1 = 0 then alpha^(2) + beta^(2) + gamma^(2) =

If alpha, beta ,gamma are the roots of x^(3) + x^(2) + x + 1 = 0 then alpha^(3) + beta^(3) + gamma^(3) =

If alpha, beta , gamma are zeroes of x^(3) + 3x^(2) - x +2 the alpha beta gamma = …………….

If alpha,beta,gamma are the zeroes of 3x^3-5x^2-11x-3 , then alpha+beta+gamma =