The ratio of the height above the surface of earth to the depth below, the surface of earth, for gravitational accelerations to be the same (assuming small heights) is 

Options

A. 0.25
B. 0.5
C. 1
D. 1.25

Answer

B

Explanation

`gh= g (1 - (2h)/(R ))" "…(1)`
`gd = g(1- (d)/(R )) " "…(2)`
On equating (1) & (2) ,
`rArr (1 - (2h)/(R )) = (1 - (d)/(R ))`
`rArr (2h)/( R ) = (d)/(R )`
`therefore (h)/(d) = (1)/(2) = 0.5`