The degree of dissociation of `0.1 N CH_3 COOH` is (given `K_a=1xx10^(-5)`) approximately

Options

A. `1xx10^(-6)`
B. `1xx10^(-7)`
C. `1xx10^(-3)`
D. `1xx10^(-2)`

Answer

D

Explanation

Degree of dissociation,
`a = sqrt((k_a)/("Concentration"))` `= sqrt((1xx 10^(-5))/(0.1))= (1)/(100) = 1 xx 10^(-2)`