The approximate molarity of a solution in mol `L ^(-1)` that contains `13.50` g of naCl dissolved in 452 mL of water is

Options

A. `0.25`
B. `0.51`
C. `1.0`
D. `1.2`

Answer

B

Explanation

Given,
Mass of `NaCl = 13.50 g`
Volume of water ` = 452 mL`
Approximate molarity of solution `= ("Mass of NaCl")/("Molar mass of NaCl ") xx ( 1000)/( "Volume of water (mL"))`
`M = ( 13.50)/( 58.44) xx (1000)/( 452) (because` Molar Mass of NaCl `= 58.44 g`)
`= ( 13500)/(2641.88) = 0.511`
`therefore M = 0.51 mol//L`