The increase in entropy in `JK^(-1)` of a substance when it absorbs 1 kJ of hear energy at 3 K is

Options

A. `3.33`
B. `333.3`
C. `0.333`
D. `0.0333`

Answer

B

Explanation

Given,
Heat energy absorbed by a substance, `q =1 KJ`
Temperature, `T =3K`
The equation for entropy is given by,
Entropy` =("Absorbed heat")/("Trmperature ")`
`Delta S = (q)/(T)`
`= (1k)/(3) = (1000)/(3) = 333.3J//K`
`therefore Detla S =333.3J//K`